Almost everyone is taught the tides as two bulges: the Moon pulls the ocean into an egg, the Earth turns under it, and you get two highs a day. The picture is tidy, it is famous, and in three separate ways it is wrong — or rather, it is a careful idealization that the real ocean ignores. Each correction is a number you can check, so let's compute them, starting with the one that sounds impossible.
Movement I · The Sun losesIt out-pulls the Moon 179 to 1 — and loses the tide
Newton's law of gravity is an inverse-square law: the force between two masses falls off as 1/d². Put in the real masses and distances and ask which body pulls the whole Earth harder. It isn't close.
Weighing the two pulls — and then the two tides
tide ratio = pull ratio ÷ distance ratio = 178.9 ÷ 389 = 0.46
Here is the whole secret. The force of gravity goes as 1/d², but a tide is not the force — it is the difference in the force across the width of the Earth, the near side pulled a little harder than the far side. Differencing an inverse-square law turns it into an inverse-cube one: the tide-raising effect goes as M/d³. The Sun is about 389 times farther than the Moon, so that extra factor of distance divides its enormous pull right back down. 179 ÷ 389 ≈ 0.46. The Sun wins the pull and loses the tide, by exactly the margin the third power demands.
Movement II · Two bulges, both realThe far bulge is not a fudge
The near-side bulge is easy: the Moon pulls the water nearest it hardest, and it heaps up. But why a bulge on the far side, pointing away from the Moon? The popular answers — "centrifugal force flings the water off," "the Earth gets pulled out from under the far ocean" — are at best bookkeeping and at worst nonsense. The honest answer is that the tidal force is the gradient of gravity, and a gradient points outward on both ends. Drag the Moon and watch the actual field.
The tidal force field — drag the Moon around the Earth
Subtract the pull on the Earth's centre from the pull at each point of the surface — that residual is the tide. At the point nearest the Moon the residual points toward the Moon (outward). At the point farthest away, gravity is weaker than at the centre, so relative to the centre the water there is left behind — and "left behind on the far side" means heaped outward, away from the Moon. Computed exactly from the inverse-square law, the far bulge comes out at 1.07×10⁻⁶ m/s² against the near side's 1.13×10⁻⁶: real, outward, and only about 5% smaller. Not absent. Not centrifugal. Just the difference of a force across eight thousand kilometres of rock.
Why the Sun shows up anyway — spring and neap
The Sun's tide is 0.46 of the Moon's — small, but not nothing. When the two line up (new Moon and full Moon) their bulges add; when they pull at right angles (the quarter Moons) the Sun's bulge sits in the Moon's trough and partly cancels it. That is the two-week swing every tide table shows: the big spring tides and the meek neap ones. Pick a phase.
The combined equilibrium tide, by Moon phase
Spring tides aren't seasonal — "spring" is from the old sense of welling up. They follow the Moon's phase, every fortnight, year-round.
And the bulges aren't the ocean
Now the honest part, the one most pages skip. Everything above is equilibrium theory — Newton's idealization, in which the ocean has time to settle into the static egg the Moon's gravity wants. Compute how big that egg is, and the textbook's own picture quietly falls apart.
The equilibrium high tide comes to about 0.36 m for the Moon and 0.16 m for the Sun — a combined spring range, high to low, of about 0.78 m. Three-quarters of a metre. The Bay of Fundy gets sixteen metres. The equilibrium bulge is off by more than a factor of twenty, and no refinement of Newton's static ocean will ever close that gap, because the static ocean is the wrong model. Here is why it has to be:
The bulge can't keep up with the Moon
A tide is a wave, and a wave in water of depth H can move no faster than √(gH). With the ocean's mean depth of ~3.7 km that ceiling is about 190 m/s. But the point beneath the Moon races west around the equator at 465 m/s — more than twice the speed the water could ever chase it at. The bulge is asked to run a race it physically cannot run.
So the real ocean never reaches equilibrium. Instead the tide behaves as a forced wave sloshing in the basins, the way water in a carried bowl heaps at the walls — Laplace's dynamic theory (Paris Académie, 1775–76), the equations we still solve. In a basin the tide runs around the edges as a rotary wave, pivoting about still points called amphidromic points where the range falls to nearly zero. William Whewell predicted such a no-tide point in the North Sea in 1836; the surveyor William Hewett sailed out and confirmed it in 1840. There are roughly a dozen major amphidromic systems for the principal lunar tide, give or take how you count them — and around each one, high tide arrives at a different hour at every port on the shore.
Which kills the last piece of the cartoon: at most places, high tide does not happen when the Moon is overhead. The lag — sailors called it the establishment of the port — is a fixed local number you can read off a chart, and it has nothing to do with a bulge sitting under the Moon, because there is no such bulge. The Moon sets the rhythm; the shape of the sea floor sets everything else.
The two-bulge story isn't a lie so much as a first chord. It gets the cause right (gravity's gradient), the cadence right (twice a day, springs every fortnight), and the actual water almost entirely wrong. The honest version is better: a wave too slow to follow its own Moon, pivoting around invisible still points, piling sixteen metres into one Canadian bay and nothing at all into a patch of the North Sea — all of it forced by a difference in gravity so small you'd need a hundred-thousandth of Earth's own pull to measure it.
Show the check
Every figure on this page is recomputed from published constants — masses, distances, the gravitational constant, the sidereal day, the mean ocean depth — by a standalone script. Run it yourself:
node research/the-tide-textbook-got-wrong/verify.mjs → 21/21 checks passed
It derives the 179× pull ratio and the 0.46 tide ratio independently and proves they satisfy the identity tide = pull ÷ distance; computes the near- and far-side tidal accelerations from the exact differential of GM/r² (not the textbook approximation) and shows both point outward; gets the equilibrium bulge heights and the spring/neap ranges; and confirms the forcing point (465 m/s) outruns the shallow-water wave (190 m/s), so no equilibrium bulge can form. What it does not prove — and the page does not assert as derived — is the law of gravity itself, the global map of amphidromic points (those come from solving Laplace's equations on the real basins, named here, not re-derived), or the Bay of Fundy record (a cited observation).
Sources & honest edges
- · Constants: CODATA 2018 (G); IAU 2015 / NASA fact sheets (masses, radii, distances); IAU 2012 (the astronomical unit).
- · Equilibrium theory: Newton, Principia (1687) — the static two-bulge idealization, an assumption about an imaginary instantaneously-adjusting ocean, never a claim about the real one.
- · Dynamic theory: Laplace, memoirs to the Paris Académie des Sciences (1775–76) — the Laplace tidal equations.
- · Amphidromic points: Whewell's predicted North Sea no-tide point (1836), confirmed by Hewett (1840). The count of "roughly a dozen" major M2 systems varies by counting convention.
- · Highest tides: Bay of Fundy great spring range ~16 m (max ~16.3 m, Burntcoat Head; NOAA). The title is genuinely contested — a 2024–25 Makivvik survey of Leaf Basin in Ungava Bay reported a comparable ~16.4 m range; not yet certified.
- · The far bulge is the gravitational gradient, not centrifugal "flinging" (NOAA Ocean Service tides tutorial; Baird, West Texas A&M "Science Questions").